Assume that the average protein in e. coli consists of a chain of 400 amino acids. what is the maximum number of proteins that can be coded

Assume that the average protein in E.coli consists of a chain of 400 amino acids.  Now, a single amino acid present in the protein requires a codon to code for it. A codon consists of 3 nucleotides. This shows that a protein of length 400 amino acids will require, 400 codons to code for it, that is, 1200 (3 x 400) nucleotides are required. We know that the length of the E.coli genome on average is 5 x base pairs.

1200 nucleotides = 1 protein

5 x nucleotides = X no. of proteins

X = = 4167

The answer is 4167 proteins.

you did not attach the discourse, but i assume it to be the discourse on the origin and basis of inequality among men (the original titile in french is: "discours sur l'origine et les fondements de l'inégalité parmi les hommes"), also know as "second discourse". in this discourse, jean-jacques rousseau emphasizes that private property is the basis of all inequalities.

therefore, what enabled the old regime to maintain as long as it did was private property.

c is the answer : )               your welcome