Plant height in pea plants is dominant (t). in a wild crop of 8,216 plants, 3,122 are short (tt). how many plants are homozygous dominant? how many are heterozygous and how many are homozygous recessive?

Dominant allele for height T

Recessive allele t

Genotypes for tall Tt or TT

Genotype for short tt.

If there is 8,216 plants, 3,122 are short, which means that 5094 are tall.

Frequency of the recessive homozygous is q2 and it is 3122/8216=0.38, which means that only q=0.62

If p+q=1 (HW equilibrium), than p=0.38

Frequency of dominant homozygous is p2=0.14

The number of dominant homozygous is 0.14*8216=1183

The number of heterozygous is 5094-1183=3911

The number of recessive homozygous is 3122

it has to be understood that the sea water contains a huge amount of sodium and chlorine ions and if they enter the cell of the atlantic cod fish, the cell will shrivel and the fish will die. to avoid such a condition, the fish uses active transport for the purpose of removing the ions against the gradient.

explanation:

the atlantic cod is not a maritime osmoconformer. its native application of salts is less than that of the seawater it lives in. it is continually falling water from the gills to the ocean via osmosis.

countering that, the fish is going to be swallowing seawater. but since its internal collection of salts is lower than seawater, the fish will want to go free of excess salt, and since that's going upon a gradient, then active transport, requiring energy, must be used to pump out the salt. much marine fish use the organs to filter out the salt and these fish discharge very straight urine.