Biology, 30.06.2019 23:00 FloweyFlower
Eukaryotic initiation: 1) and bind to the small and large ribosomal subunits respectively to prevent them from without mrna 2) complex is formed. 3) complex is formed. 4) cells can regulate protein synthesis by a residue on the bound to gdp. the phosphorylated complex is unable to exchange the bound gdp for gtp and cannot bind thus inhibiting protein synthesis. 5) as the mature mrna is transported from the nucleus into the cytoplasm, initiation factors for protein synthesis binds to the 6) the binds to the to form the through an interaction of the subunit and the initiation complex then along the mrna to look for the kozak sequence containing the first aug. 7) the helicase which is activated by uses atp to unwind rna structures. 8) scanning as the met-trnaimet anticodon the aug codon (kozack sequence). 9) hydrolyzes to eif2-gdp, an irreversible step that prevents further scanning. 10) the eifs 11) bring in ; gtp is hydrolized and the ifs are released. 12) met- trnaimet positioned at the _ site.
Answers: 1
Biology, 21.06.2019 18:30
Describe the primary and secondary immune response in terms of speed and number of antibodies produced?
Answers: 3
Biology, 21.06.2019 22:00
Drag each label to the correct location. each label can be moved more than once match the properties with the subatomic particle
Answers: 3
Biology, 21.06.2019 23:40
Explain the difference between incomplete dominance and codominance
Answers: 2
Biology, 22.06.2019 01:00
Why reason best illustrates why hershey and chase chose to use viruses in their experiment?
Answers: 2
Eukaryotic initiation: 1) and bind to the small and large ribosomal subunits respectively to prev...
Health, 11.05.2021 08:00
Mathematics, 11.05.2021 08:00
Mathematics, 11.05.2021 08:00
Spanish, 11.05.2021 08:00
Social Studies, 11.05.2021 08:00
Mathematics, 11.05.2021 08:00
History, 11.05.2021 08:00