In the previous question, you used the hardy-weinberg equation to determine the frequencies of the genotypes for hh, hh, and hh, given gene frequencies of h = 0.2 and h = 0.8. these frequencies were: hh = 0.04 hh = 0.32 hh = 0.64 now, determine the expected numbers of each organism in the population (total size = 150): number of hh = number of hh = number of hh =

If frequencies are: HH = 0.04 Hh = 0.32 hh = 0.64, this expressed in the percentage is 4%, 32% and 64%  (4+32+64=100) respectively. If the total number of organisms in population is 150 then:  

Number of organisms with HH genotype is 0.4*150= 6

Number of organisms with Hh genotype is 0.32*150=48

Number of organisms with hh genotype is 0.64*150=96

6+48+96=150

the answer is; comparing the frequency of collisions with and without the device

this makes the anti-collision system an independent variable and the collisions a dependent variable. if there are fewer collisions with an anti-collision system that without, then it can be stated that the system is a success. essentially, collisions under an anti-collision system are compared with the frequency of collisions by cars with the human drivers.

i think a) betsy can donate only blood to mark is correct because, mark and betsy have the same blood type. whereas nobody else has b+ blood so betsy can't donate to them.