P2 + 2pq + q2 = 1 in the hardy weinberg formula, what algebraic term is used to find the number of heterozygous individuals in a population?

 The answer is:  " 2pq " .

Note: (p+q) (p+q) = ?  

Note the following "distributive property" of multiplication:

        (a + b) (c + d) = ac + ad + bc + bd ;

As such:

(p + q) (p + q) = pp + pq + qp + qq ;

                →   =  pp + pq + pq + qq ;

Combine the "like terms:

  pq + pq = 2pq ;   Note there these are the "heterozygous" individuals in the population;  since these represent "2 different alleles" ;  

                   = p² + 2pq + q²  ;

       Since:  "pp" ; or:  "p² "  is:  "homozygous" (the same 2 alleles)" ;

and since:  "qq" ; or:  "q² "  is:  "homozygous (the same 2 alleles)" .  

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