The double-stranded dna molecule of the newly discovered elradicus libanii has a length of 34 micrometers. how many base pairs are present in this molecule?

100 000

Explanation:

The average length of a base pair (bp) is 340 pm [340 × 10^(-12) m]

Length of DNA = No. of bp × length of bp

34 × 10^-6 m = n × 340 × 10^-12 m

n = (34 × 10^-6)/(340 × 10^-12) = 100 000

The DNA molecule contains 100 000 base pairs.

ok

explanation:

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