What is the expected phenotypic ratio from a cross of heterozygotes (a1a2 x a1a2) for a phenotype that expresses incomplete dominance?
a. 1: 1: 1: 1
b. 1: 1
c. 1: 2: 1
d. 3: 1

c. 1:2:1

Explanation:

To know the probabilities of the offspring, you need to draw a Punnett square and cross both genes.

In this case, you have two heterozygous genes with incomplete dominance, this means, there's no dominant or recessive allele.

If you cross A1A2 and A1A2, you'll have A1A1, A1A2, A2A1, and A2A2 this is equal to say 1:2:1 if you want to talk about phenotypes.

sex cells are usually half's then they find another half and make a fertilize egg

i think the answer is composed of atoms