If a single bacteriophage infects one e. coli cell present on a lawn of bacteria and, upon lysis, yields 175 viable viruses, how many phages will exist in a single plaque if 3 more lytic cycles occur? enter your answer to three significant digits (for example: 1.11*10^3).

9.378*10^8

Explanation:

The number of phages in each cycle

The number of host infected in each cycle

The number of phages released by each hosts in each turn  

There are total cycle .

So the total number of phages that exist in a single plaque if 3 more lytic cycles occur

actually the answer is c