Glucose-6-phosphate dehydrogenase (g6pd) deficiency is inherited as an x-linked recessive gene in humans. a woman whose father suffered from g6pd marries a normal man. what proportion of their sons is expected to have g6pd? enter your answer as a fraction.

1/2

Explanation:

Let us assume that the presence of "g" allele on the X chromosome causes the disease. An X linked recessive disease is passed from an affected male to his daughters. A female with one copy of "g" allele on her X chromosome would serve as carrier for the disease while the female with two copies of "g" alleles would be affected with the disease.  

A male with one copy of the "g" allele on his X chromosome would be affected with the disease. This is due to the fact that human males are hemizygous for X linked genes.  

Given that the female had the affected father, the genotype of the female would be "X^gX". The genotype of the normal man would be "XY". A cross between carrier female and normal male would give 1/2 affected sons.  

vodka and hennesy

explanation:

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