In guinea pigs hair straightness or curliness is thought to be governed by a single pair of alleles showing incomplete dominance. individuals with straight hair are homozygous for the s allele, those with curly hair are homozygous for the c allele, and individuals with wavy hair are heterozygous (sc). you collect data on 1,000 individuals from a population and discover that 244 have straight hair, 444 have curly hair, and 312 have wavy hair. a) calculate the allele frequencies of the s and c alleles. b.) is this population in hardy-weinberg equilibrium? show work to support your answer.

Frequency of allele S is p

Frequency of allele C is q

The population is not in Hardy-Weinberg equilibrium

Explanation:

Given -

Number of individuals with straight hair

Number of individuals with curly hair

Number of individuals with Wavy hair

Let "p" represents the frequency for allele for straight hair and "q" represents the frequency for allele for curly hair

represents the frequency of genotype "SS"

represents the frequency of genotype "CC"

represents the frequency of genotype "SC"

Frequency of allele S is p

Frequency of allele C is q

tex]= \sqrt{0.444} \\= 0.666[/tex]

For being in Hardy Weinberg's equation-

Substituting the values in above equation, we get -

hence, the population is not in Hardy-Weinberg equilibrium