Which of the following represents the correct sequence of events in bacterial translational initiation?
a. 30s binds shine-dalgarno --> n-formylmet-trna binds aug --> 5qs binds 2nd aminoacyl-trna binds in the p site
b. 50s binds shine-dalgarno --> n-formylmet-trna binds aug --> 30s binds 2nd aminoacyl-trna binds in the a site
c. 30s binds shine-dalgarno --> n-formylmet-trna binds aug --> 50s binds 2nd aminoacyl-trna binds in the a site
d. 30s binds shine-dalgarno --> 50s binds n-formylmet-trna binds aug --> 2nd aminoacyl-trna binds in the a site

c) 30S binds Shine-dalgarno → N-formylMet-tRNA binds AUG  → 50S binds  → 2nd aminoacyl-tRNA binds in the A site.

Explanation:

The first step in formation of 70S initiation complex in bacterial translational initiation includes binding of 30S rRNA subunit to Shine-dalgarno sequence present on mRNA.

Soon after that N-formylMet-tRNA binds AUG (start codon) which is present on mRNA.

There are two sites in 30S rRNA which are P site and A site. The first tRNA mentioned above i.e. N-formylMet-tRNA is adjusted in P site. Then after the larger rRNA subunit which is known as 50S joins the complex.

Once the 70S initiation complex has formed, a 2nd aminoacyl-tRNA enters the complex and gets adjusted in A site located in 30S rRNA.

a. seed plant structure. 1. the three main plant organs are roots, stems, and leaves. a fourth kind of tissue, meristematic tissue, is responsible for plant growth. meristematic tissue is the only plant tissue that produces new cells by mitosis. plants can lose water out of their leaves as they exchange gases with the air

explanation:

the correct answer in apex is tissue development, i know because i just had this question