You have screened for several new recessive mutations in a species of wasp. wasps homozygous for apricot (aa) have pale orange eyes. (wild-type eyes are brown.) wasps homozygous for blunt (bb) have short wings. (wild-type wings are long.) you make a pure-breeding double-mutant (apricot, blunt) line and cross it with wild-type wasps. the f1 is wild-type in appearance.

The F1 will have mostly dominant phenotype, nevertheless, some recesive phenotype appears as aa - ab and bb

Explanation:

If you make a pure-breeding double-mutant (apricot, blunt) line - you will have heterozygous ab

and if you cross it with wild-type wasps - you will have for apricot: AA - Aa and for blunt BB - Bb (as A and B are dominant gen)

Then, you could have for F1 breed:

*- ab / AA: Aa - BA

*- ab / Aa: aA - aa - bA - ba

*- ab / BB: Ba - aB

*- ab / Bb: aB - ab - bB - bb

your answer should be c) enjoy!

cuz he's blad

explanation: