You are breeding two polyploid species of cabbage. you cross the two different species (parent 1 x parent 2) and obtain f1 hybrids. the following meiotic pairing was observed in the f1 hybrid: f1 hybrid = 9 bivalents + 9 univalents a) how many chromosomes are there in a non-dividing somatic cell of an f1 plant (i. e. what is the organisms ploidy)? b) how many chromosomes are there in a non-dividing somatic cell of each parent (i. e. what is the organisms ploidy)?

1) 36 chromosomes

2) Parent 1 = 24 chromosomes

   Non dividing somatic cells = 12 chromosomes

Explanation:

Given data:

F1 hybrid = 9 bivalents + 9 univalents

A. The plant that does not divide F1 has 12 univalents + 12 bivalents. It has 36 chromosomes in total.

Note: 1 bivalent chromosomes consist of 2 chromosomes

B. That parent's non-dividing somatic cell comprises 12 chromosomes, while the number is 24 for parent 1.

Parent 1 = 24 chromosomes

Non dividing somatic cells = 12 chromosomes

white blood cells or wbc s are mainly 2 types-

1.agranulocytes

2.granulocytes

the monocytes or macrophages of agranulocytes , dendritic cells which are accessory leucocytes, and b cells which is one type of lymphocytes   identify the antigens present on the pathogen's surface. these three cells are called antigen presenting cells(apc) which are phagocytes and destroy the antigens by secreting antitoxins. besides this leukocyte is always plays vital role in the immunity of the body.