Color blindness is a recessive x-linked trait in humans. in a family where the mother is heterozygous for color blindness and the father is color-blind, the probability of their having a color-blind daughter is:
a.0.
b.1.
c.1/4.
d.1/2.
e.1/16.

1/2

Explanation:

Genotype of the heterozygous mother= X^cX

Genotype of color-blind father= X^cY

A cross between heterozygous mother and color blind father would give progeny in following phenotype ratio=

1 colorblind daughter: 1 colorblind son: 1 carrier but normal daughter: 1 normal son.

Therefore, this couple has 1/2 probability of getting a colorblind daughter is 1/2

youre right there are

hammurabi rulers

good lesson