There is a certain dominant/recessive gene in a population, where the dominant allele is referenced as "a", and the recessive variant as "a". the population has 1000 individuals. if the population is known to have 160 individuals that show the recessive trait, how many of the individuals who show the dominant trait are heterozygotes? what are the values of "p" and "q"?

Number of heterozygotes = 480

p = 0.6

q = 0.4

Explanation:

Assuming the population is in Hardy-Weinberg Equilibrium,

p + q = 1

p² + 2pq + q² = 1

where,

p = frequency of dominant allele

q = frequency of recessive allele

p² = frequency of dominant homozygous population

2pq = frequency of heterozygous population

q² = frequency of recessive homozygous population

Here,

frequency of aa = q² = 160/1000 = 0.16

q = √0.16 = 0.4

p = 1-q = 1-0.4 = 0.6

frequency of Aa = 2pq = 2 * 0.6 * 0.4 = 0.48

Number of Aa heterozygotes = 1000 * 0.48 = 480

water is a polar molecule. a chemical bond is a force of attraction between atoms or ions. bonds form when atoms share or transfer valence electrons. atoms form chemical bonds to achieve a full outer energy level, which is the most stable arrangement of electrons. so, false

explanation:

in h2o molecule, two water molecules are bonded by a hydrogen bond but the bond between two h - o bonds within a water molecule are covalent. the greater the electronegativity difference, the more ionic the bond is. bonds that are partly ionic are called polar covalent bonds. nonpolar covalent bonds, with equal sharing of the bond electrons, arise when the electronegativities of the two atoms are equal.