"labrador retrievers come in three colors: black, brown, and yellow. coat color among labradors arises through the interaction between the alleles of two genes. one gene produces melanin. allele b (black) is dominant to allele b (brown). another gene, a regulatory gene, affects the deposition of pigment in individual hairs. allele e promotes the deposition but in the recessive homozygote (ee) the gene blocks deposition and a yellow coat results. what are the phenotypic ratios of the f1 generation offspring of two dihybrids

4/16 yellow Labradors, 9/16 black Labradors and 3/16 brown Labradors.

Explanation: Two dihybrids would have BbEe alleles. Using Mendel's chess table of independent segregation to show the offspring,  we have the following results:

BBee - 1/16 - yellow

BBEe - 2/16 - black

BBEE - 1/16 - black

BbEe - 4/16 - black

Bbee - 2/16 - yellow

BbEE - 2/16 - black

bbEe - 2/16 - brown

bbEE - 1/16 - brown

bbee - 1/16 - yellow

If the offspring presents B_E_ phenotypes, it will have black pigment deposition. If the offspring presents bbE_ phenotypes, it will have brown pigment deposition. Otherwise, if it presents _ _ee phenotypes, there won't be any pigment deposition, therefore they are yellow.

Adding up all the phenotypes ratios, we have 4/16 yellow Labradors, 9/16 black Labradors and 3/16 brown Labradors.

1. what is the relationship between the shape of an enzyme and the reactions they catalyze?

2. how does an enzyme inhibitor work?

separate your answers so i dont get confused : )

only about ten percent of the energy at one trophic level is passed on to organisms at the next trophic level. the remainder of the energy is used in life processes or lost as heat.