In a cross between two doubly heterozygous dontdrinkmycola flowers, the following number of offspring are produced: 471 offspring with mauve colored petals, and 29 teal-colored petals. the most likely form of epistasis here is:

Duplicate dominant epistasis

Explanation:

The cross of two doubly heterozygous individuals is a dihybrid cross AaBb x AaBb. From Mendel's law of independent assortment we expect the following phenotypic ratios in the offspring:

The cross of doubly heterozygous Dontdrinkmycola flowers produced 471 offspring with mauve colored petals, and 29 teal-colored petals (total: 500).

The ratios are:

471/500 ≅ 15/16

29/500 ≅ 1/16

So the ratios are 15:1 and the most likely form of epistasis is duplicate dominant epistasis, where a single copy of a dominant allele of either gene is enough to produce the dominant phenotype (mauve colored petals).

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