If a husband and wife have a heterozygous girl for colorblindness a normal boy, a colorblind girl, and a colorblind boy what would be the genotypes of the parents?

The Wife is a carrier of the recessive allele with a genotype XX°

The husband is a colorblind individual with Genotype X°Y

Explanation:

Now let us consider the case of the colorblind daughter ,

Now, Let us consider the case of a Normal Boy:

On considering both cases stated above we can conclude that the woman is a carrier of the recessive trait while father expresses the disease and has the X-chromosome with the recessive allele.

This is further confirmed by presence of a heterozygous daughter whose genotype is XX°. She has received the normal X from mother and the mutated X from the father.

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