Suppose that we are dealing with four genes, each gene consisting of a dominant allele (capital letter) and a recessive allele (small case letter). if the cross ccmmllpp x ccmmllpp is made, what is the probability of obtaining an individual who is ccmmllpp?

1/16

Explanation:

The desired genotype is "CcmmLLPp". The proportion of the desired genotype can be calculated by using the product rule. The probability of getting Cc, mm, LL and Pp genotype can be calculated separately first and then the product rule is applied.  

Parents= CcMmLlPP X CCmmLlpp

Cc x CC= 1/2 Cc: 1/2 CC

Mm x mm= 1/2 Mm: 1/2 mm

Ll x Ll = 1/4 LL: 1/2 Ll: 1.4 ll

PP x pp= All Pp

Therefore, the probability of obtaining an individual who is CcmmLLPp = 1/2 Cc x 1/2 mm x 1/4 LL x 1 Pp = 1/2 x 1/2 x 1/4 =1/16

i believe that the answer is c.

the answer to this question is a