Use the following information to solve the problem using a punnett square. assume that the dominant "b" allele encodes brown eyes and the recessive "b" allele encodes blue eyes. an individual with the genotype bb has children by mating with an individual of the genotype bb. what is the percent chance that they would have children with blue eyes?

0%

Explanation:

From the information given;

Assume that the dominant "B" allele encodes brown eyes ; and

the recessive "b" allele encodes blue eyes

If genotype BB ×  genotype bb, the percentage of chance that they would have children with blue eyes will be zero ...Let look at the cross

BB × bb

We have all the progeny as Bb, Bb, Bb, Bb  i.e the genotypic information are all heterozygous brown eyes, this is because The allele B mask the recessive "b" allele which makes the allele B (brown eyes) to be dominant over allele b (blue eyes).

i would say the prokaryotic cells the prokaryotic cells are less complex, are usually found only in unicellular organisms and have more limited capabilities than eukaryotic cells.