The human genome sequence shows that genes a and b are at opposite ends of chromosome 9. if an individual who is heterozygous for both genes (aabb) mates with an individual that is homozygous recessive for both genes (aabb), how many of their offspring would show a recombinant phenotype?

8 offsprings (50%)

Explanation:

When genes are on the same chromosome but very far apart, they assort independently due to crossing over (homologous recombination).

When genes are far apart, crossing over happens often enough that all types of gametes are produced with 25% frequency.

When AaBb × aabb; the offsprings are as follows:

= AaBb, Aabb, aaBb, aabb

= AaBb, Aabb, aaBb, aabb

= AaBb, Aabb, aaBb, aabb

= AaBb, Aabb, aaBb, aabb

Recombinants phenotypes of linked genes are those combinations of genes not found in the parents.

From the cross above, it is obvious that only 8 offsprings are quite different from their parents.

To calculate the recombinant frequecy, we  divide  (no of recombinant/ total no of offsprings) × 100%

=(8/16) × 100%

= 1/2 × 100%

=0.5 × 100%

= 50%

bc blah

explanation:

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a. seed plant structure. 1. the three main plant organs are roots, stems, and leaves. a fourth kind of tissue, meristematic tissue, is responsible for plant growth. meristematic tissue is the only plant tissue that produces new cells by mitosis. plants can lose water out of their leaves as they exchange gases with the air

explanation: