Acolor blind man without hemophilia (both x-linked traits) marries a woman who is a carrier for both traits. what is the probability they will have a son with both color blindness and hemophilia? hemophilia and color blindness are unlinked genes.

a. 1/1
b. 1/16
c. 1/8
d. 1/4
e. 3/16

Option D.

Explanation:

Both genes are linked to X chromosome. They are  recessive diseases and a heterozygous gene, which means that two different forms of a particular gene are inherited, one from each parent.

CB : Color blindness carrier, healthy

H: Hemophilia carrier, healthy

h: Disease

cb: Disease

Mom: X(CB/H) X(cb/h) (carrier)

Dad: X(cb/H) Y (color blind man, and  dominant for hemophilia - healthy)

Let's make a table

MOM/DAD |  X(CB/H) X(cb/h)   |

X(cb/H)Y    |   X(cb/H) X(CB/H)  |   Healthy girl for H, carrier for cb

X(cb/H)Y    |   X(cb/H) X(cb/h)   |    Healthy girl for H, sick for cb

X(cb/H)Y    |   Y  X(cb/h)    |  Boy sick for cb and h  

X(cb/H)Y    |   Y  X(CB/H)    |  Boy healthy for CB and H

1 probable case, over 4 possible cases

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