Acricket has a diploid genome of 1.2 billion base pairs. assume that there are about 200,000 individuals in the population and that the mutation rate is one per 100 million base pairs. about how many new mutations will occur in each generation of the population of crickets?
a. 1.2b. 12c. 200,000d. 1 millione. 2.4 mllion

Option E 2.4 million

Explanation:

Data provided in the question:

Diploid genome of cricket = 1.2 billion base pairs

Number of Individuals in the population = 200,000

Mutation rate = 1 per 100 million base pairs

Now,

Number of mutation per individual = Total number of bases × Mutation rate

= 1.2 billion ×  1 per 100 million base pairs

= 1,200,000,000 × (1 ÷ 100,000,000 )

= 12 mutation per individual

Therefore,

Number of new mutation in the given population

= Number of mutation per individual × Number of Individuals in the population

= 12 × 200,000

= 2,400,000

= 2.4 million

Option E 2.4 million

after making a punnet square using bv bv bv bv you will find that the ratio will be 9: 7 or a 128.6% probability.

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