the hardy-weinberg equation is as follows:
![p^{2}+2pq+ q^{2}=1](/tex.php?f= p^{2}+2pq+ q^{2}=1 )
where
is homozygous dominant, 2pq is heterozygous, and
is recessive.
we also know that:
![p+q=1](/tex.php?f= p+q=1 )
so since we know that homozygous dominant is 0.53, we can solve for p:
![p^{2}=0.53](/tex.php?f= p^{2}=0.53 )
![p=0.728](/tex.php?f= p=0.728 )
so then we can solve for q:
![0.728+q=1](/tex.php?f= 0.728+q=1 )
![q=0.272](/tex.php?f= q=0.272 )
so then we can solve for the heterozygous term:
![2pq = 2(0.728)(0.272)=0.396](/tex.php?f= 2pq = 2(0.728)(0.272)=0.396 )
so now we know that the percentage of the population that should be heterozygous is 39.6%.