In a first order decomposition, how long does it take (in seconds) for 40% of the compound to decompose given that k is 0.0284 sec-1 (give answer to 1 decimal place)?

t = 18 s

Explanation:

given,

decomposition of the material = 40 %

Remaining percentage of the material = 100 -40 = 60 %

k = 0.0284 sec⁻¹

Using equation of first order of decomposition

A is the material left after decomposition

A_0 is the initial size of material before decomposition.

      t = 18 s

Time taken to decompose 40% is equal to 18 s.

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