Calculate the osmotic pressure of a solution containing 19.15 mg of hemoglobin in 15.4 mL of solution at 29 ∘C . The molar mass of hemoglobin is 6.5×104 g/mol.

47565.9 atm

Explanation:

Number of moles = mass/molar mass

= 19.15 × 10^-3/6.5 × 10^4

= 29.46 mol.

V = 15.4 x 10^-3 L

R = 0.08205746 L.atm/K.mol

T = 30 + 273K

= 303 K

Using PV = nRT

P = (29.46 * 0.08205746 * 303)/0.0154

= 47565.9 atm

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