Assuming a stroke volume output of 75 ml at rest that increases by 24% after exercise, and a heart rate of 65 at rest and 139 following exercise, calculate the cardiac output standing at rest and immediately after exercise. a. 4875/12927b. 4875/10425c. 4875/6045d. impossible; subject would be dead with a heart rate of 139 bpm.

4875/12927.

Explanation:

The cardiac output may be defined as the product of the heart rate and the stroke volume.

Cardiac output= stroke volume ×heart rate

The cardiac output at rest can be calculated as follows:

The stroke volume at rest is 75 and the heart rate is 65.

Cardiac output = 75×65

Cardiac output = 4875 .

The cardiac output after exercise can be calculated as follows:

The stroke volume has been increased by 24%.

Final stroke volume = 75 × 24/100 + 75

Final stroke volume = 93.

Heart rate = 139.

Cardiac output = 139×93

Cardiac output = 12927 .

Thus, the answer is 4875/12927.

oxygen +1 most likely

it has to be understood that the sea water contains a huge amount of sodium and chlorine ions and if they enter the cell of the atlantic cod fish, the cell will shrivel and the fish will die. to avoid such a condition, the fish uses active transport for the purpose of removing the ions against the gradient.

explanation:

the atlantic cod is not a maritime osmoconformer. its native application of salts is less than that of the seawater it lives in. it is continually falling water from the gills to the ocean via osmosis.

countering that, the fish is going to be swallowing seawater. but since its internal collection of salts is lower than seawater, the fish will want to go free of excess salt, and since that's going upon a gradient, then active transport, requiring energy, must be used to pump out the salt. much marine fish use the organs to filter out the salt and these fish discharge very straight urine.