A mouse is heterozygous at four different gene loci, with a genotype of AaBbCcDd. For each gene locus, the upper case letter represents the dominant allele and the lower case letter represents the recessive allele. These four allele pairs follow Mendel's principle of independent assortment. Knowing this, and assuming normal segregation of alleles during meiosis, complete the sentences with the correct terms. The probability that a gamete produced by this mouse will have two A alleles is .

The correct answer is - zero.

Explanation:

In the given heterozygous mouse with the genotype of AaBbCcDd, there are 4 different genes are present with there recessive forms A, B, C, and D and a, b, c, and d. In the heterozygous condition, there is always only one copy of both variants of a gene present.  

By independent assortment and law of segregation, there are multiple gametes can be formed but as there is only one copy of each gene form or allele, the chances of the having two copies any allele of particular gene such as AA, BB, CC, DD, or aa, bb, cc, dd together is not possible.

Thus, the correct answer is - zero.

i believe the answer would be b. hope it : )