G Indium has two naturally occurring isotopes: 113In with an atomic weight of 112.904 amu, and 115In with an atomic weight of 114.904 amu. If the average atomic weight for In is 114.818 amu, calculate the fraction-of-occurrences of 115In isotope. Round off the answer to three significant figures.

Fraction-of-occurrences of 115In isotope

Explanation:

As we know  weight of 113 In  isotope is equal to the sum of product of fraction-of-occurrences of two constituents isotopes and their atomic weight

------(1)

As we know sum of fraction-of-occurrences of two constituents isotopes is equal to one.

---------(2)

Substituting the given values in equation 1, we get

Substituting this value in equation 2 we get -

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explanation: