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Biology, 02.03.2020 17:43 whitakers87

You have purified the enzyme enolase from both beef heart and e. coli. enolase catalyzes the conversion of 2-phosphoglycerate to phosphoenolpyruvate. you have carried out preliminary kinetic analysis and obtained the following data: Enzym source Km VmaxBeef Heart 1.9x10^-3 M 290 nmol/minE. Coli 24x10^-6 M 18 nmol/minYour boss ask you which enzyme is more efficient. What is your answer and why?

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