What is the expected Hardy-Weinberg frequency of heterozygotes in a population of green anoles, where the locus under investigation has two alleles and the frequency of one allele is 0.005 (give your answer to five decimal places)?

0.00995

Explanation:

If the population is in Hardy Weinberg Equilibrium, the sum total of frequencies of the alleles of a locus would be one. The frequency of one allele for a locus is 0.005. So, the frequency of the other allele for the same locus would be=1-0.005= 0.995

According to the given information, there are only two alleles for the locus in the population. So, the frequency of heterozygous genotype in a population= 2 x frequency of one allele x frequency of other allele= 2 x 0.005 x 0.995= 0.00995

answer: node would be introduced.   is the correct

explanation: