A plant with round seeds is crossed with a plant with wrinkled seeds. Draw a Punnett square to predict the outcome
of this cross. List the possible genotypes and their phenotypes. You may need to draw more than one punnet
square. (Note: Round is dominant to wrinkled)

Explanation:

A cross between plants with round seeds (RR) and plants with wrinkled seeds (rr).  If both parents are homozygous, having one type of gamete each, i.e. R from round seed parent and r from wrinkled seed parent (RR X rr).

    R     R

r   Rr     Rr

r   Rr     Rr

All the offspring of generation would be round with genetic constitution Rr. They will be heterozygous plants having two different alleles.  

If both parents has heterozygous round seeds with genotype Rr. So, we have Rr × Rr. The gametes produced from each of the parents are of two types, R and r.

     R      r

R    RR    Rr

r     Rr      rr

The generation has a genotypic ratio of 1 RR : 2 Rr : 1 rr. The phenotypic ratio is 3 round : 1 wrinkled.

i think the answer is gold im not entirely sure