Consider a human blood type called the MN type, which is determined by two codominant alleles, M and N. An Eskimo population in East Greenland has 200 people, 168 were MM, 30 were MN, and 2 were NN genotypes, respectively. Referring to the above question, the (observed) frequency of NN in the population is:0.0750.60.850.01Referring to the above question, if the population is under Hard-Weinberg (HW) equilibrium, the expected genotype frequency of NN will be0.00710.8370.01Referring to the above question, what is the degree of freedom you use in finding the chi-square value in the table.3142

- 0.01.

-0.01.

-1.

Explanation:

It is given that the population is under the hardy weinberg equilibrium, the observed frequency of NN can be calculated as follows;

Let the MM frequency be p² = 168

Let the MN frequency be 2pq = 30

Let the NN frequency be q² = 2.

q² = Individuals with NN / Total no. of individual.

q²= 2/ 200= 0.01.

Then, q = 0.1.

The degree of freedom = Number of allele - 1.

Here, Number of allele = 2.

Degree of freedom = 2-1.

Degree of freedom = 1.

Thus, the answer is - 0.01.

-0.01.

-1.

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explanation:

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