Imagine that we mate two black Labrador dogs with normal vision and find that three of the puppies are like the parents, but one puppy is chocolate with normal vision and another is black with PRA (progressive retinal atrophy, a serious disease of vision). We can conclude that .A) both of the parents are homozygous for both traits. B) the same alleles that control coat color can also cause PRA. C) the alleles for color and vision segregate independently during gamete formation. D) the alleles for color and vision segregate dependently during gamete formation.

Explanation:

Both parents have black color and normal vision but some of their progenies show brown color and some shows PRA, this reveals the brown coat color and PRA are recessive traits and both parents are heterozygous. The progenies include black normal vision, brown normal vision and black, PRA, that is the alleles for these genes separate independently of each other.

Let us denote the alleles as B-black, b-brown and P-normal vision, p-PRA, then the genotype of the heterozygous parent is BbPp, alleles separate independently of each other so the possible gametes are alleles for the color and vision segregate independently during gamete formation.

Thus, option C is correct.

do yall know the answer?

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