In pea plants, flower position can be axial or terminal and stem length can be long or dwarf. Axial flower position is dominant over terminal; and long stem length is dominant over dwarf. Pea plants heterozygous for both traits are allowed to self-pollinate in a dihybrid cross. 400 of the resulting seeds are planted. How many offspring would be predicted to have terminal flowers and be dwarf?

25

Explanation:

Let stem length be represented by T and t alleles ( T is dominant over t ) and flower position be represented by A and a alleles ( A is dominant over a ).

A dihybrid cross of heterozygous pea plants will give progeny in following ratio:

TtAa  X  TtAa :

T_A_ = 9

ttA_   = 3

T_aa  = 3

ttaa     = 1

So, the ratio will be 9:3:3:1 where dwarf, terminal flower plant (ttaa) will be 1/16.

If 400 seeds are planted, (1/16)*400 = 25 plants will be expected to be dwarf with terminal flowers.

the water is warmed up by the sun and then it evaporates into the atmosphere. the sunlight warms the water by its heat. water is then cooled down and condensation takes place. the water then finally returns back to the earth by the process of precipitation in the form of rain or ice.

explanation:

answer: i feel like it would be 3

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