In the common daisy, genes A and B control flower color. Both genes have a dominant allele (A or B) and a recessive allele (a or b). At least one copy of each dominant allele is required for flowers to be colorful instead of white. Predict the phenotypic ratio of the F2 progeny of a cross between two white-flowered plants, one homozygous for A and the other homozygous for B.

In F2 progeny, the phenotypic ratio will be 9/16.

Explanation:

Both A and B genes are dominant and responsible for color of daisy.

Both a and b genes are recessive and daisy will remain colorless.

Each copy of A and B must be required for daisy to be colorful.

When two white flowers are crossed, one homozygous for A and other homozygous for B.

AAbb x aaBB

Result:

According to Punnett square, in F2 progeny, 9 out of 16 daisy will colorful or the ratio will be 9/16.