From left to right the first three digits of a four digit number after 10 which digit could be in the ones place if the four digit number is divisible by 6

The digit in the unit place should be either a 2 or 8 if it is to be divisible by 6.

Explanation:

As the complete question is not given clearly, a similar question is found online and is given below:

From left to right, the first three digits of a 4-digit number add up to 6. Which digit could be in the ones place if the 4-digit number is divisible by 6?

Here the value adds up to 10 so the possible combinations are as

1+1+8

2+2+6

3+3+4

4+4+2

5+5+0

So the last number has to be such that the overall number should be divisible  by 6 (2*3) so the rule of division of 2 is simple even numbers or 0 while the odd numbers is such that the sum of the digits is divisible by 3 so the number will be divisible by 3 so

As the sum of first 3 digits is 10, the last digit such that the overall sum is divisible by 3 is either 2, 5 or 8 as 12, 15 and 18 are all the multiples of 3.

As the value has to be divisible by 2 so the only possible values in that case are even values so that is either a 2 or 8

gold i'm pretty sure i might be wrong