Biology, 29.03.2020 22:10 dontrailgrant98
What volume, in L, of 0.100 M Pb(NO3)2 is required to react completely with
45.6 mL of 0.225 M HCI?
Pb(NO3)2 + 2 HCI => PbCl2 + 2 HNO3
0.0752
0.0312
0.0523
0.103
Answers: 2
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What volume, in L, of 0.100 M Pb(NO3)2 is required to react completely with
45.6 mL of 0.225 M...
45.6 mL of 0.225 M...
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