In a study of proteins mediating cell membrane transport, microbiologists measure current versus time through the cell membranes of oocytes (nearly mature egg cells) taken from the African clawed frog, Xenopus. The measured current versus time is given approximately by I=60t+200t^2+4.0t^3, with t in seconds and I in nA. Find the total charge that flows through the cell membrane in the interval from t=0 to t=5.0s

Q(0) = 0C, Q(1) = 264nC, Q(2) = 952C Q(3) = 2088nC, Q(4) = 3696C Q(5) = 5800nC

Explanation:

I = 4t³ + 200t² + 60t

But charge of an object =》 Q = IT

Charge of an object is the product of the current and the time in which the current passes through the membrane.

When t = 0

Q = 4(0)³ + 200(0)² + 60(0) = 0C

When t = 1

Q = 4(1)³ + 200(1)² + 60(1) = 264nC

When t = 2

Q = 4(2)³ + 200(2)² + 60(2) = 952nC

When t= 3

Q = 4(3)³ + 200(3)² + 60(3) = 2088nC

When t= 4

Q = 4(4)³ + 200(4)² + 60(4) = 3696nC

When t = 5

Q = 4(5)³ + 200(5)² + 60(5) = 5800nC

i would have a lunch. it's one big package of food, making it one food. : p