A normal female X H X H marries a man who has hemophilia.

What percentage of their sons will have hemophilia?

0%

Explanation:

Normal female genotype =

Genotype of a man with hemophilia =

Crossing the two in marriage:

  x  

Progeny:

The two sons from the cross have the genotype and are therefore free from hemophilia.

Hence, the percentage of their sons that will have hemophilia is zero (0).

the answer is true when observing or determining population size, a direct observation is use, in which each organism is counted in a population or in an area. one benefit of this measure is that you get the exact population count but it will take a long time to  determine  the  size  of a  population.

multiply it by 5 in order for you to understand i cant give an exact answer.