A fruit fly population has a gene with two alleles, A1 and A2. Molecular genetic tests show that 40% of the gametes produced in the population contain the A1 allele. If the population is in Hardy-Weinberg equilibrium, what proportion of the flies are homozygous for the A1 allele?

= 0.48

Explanation:

the genetic frequency can be calculated using hardy - Weinberg equation

p + q = 1

here p represent the dominant trait and q represent the recessive trait.

the proportion A1 or p = 40/100

                                    = 0.4

now, the proportion of A2 or q will be

p + q = 1

0.4 + q = 1

q = 1- 0.4

q = 0.6

proportion of the flies are homozygous for the A1 allele

2pq

2 x 0.4 x 0.6

= 0.48

not the best question format lol but what i think might as scale color is controlled by a single gene with two alleles, the green allele and the yellow allele. when moths that are homozygous for green scales are mated with moths that are homozygous for yellow scales, 100% of the offspring have green scales.