Consider the following cross:

parent 1: yytt
parent 2: yytt

using the rules of probability, determine the probability that the offspring will show yytt genotype?

a.) 1
b.) 8
c.) 16
d.) 2

The correct answer is-

D.) 2/16

Explanation-

As per the information given in the question, the genotype of parents are-

Parent 1: YyTt

Parent 2: YyTt

Gametes produced by each parent would be- YT, Yt, yT, and yt

When these parents are allowed to cross, they will produce nine different types of genotypes out of which the probability of offspring showing YyTT would be genotype 2/16

Refer punnet square.  

explanation:

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the correct answer is sex-linked recessive.

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