If 4% of 1,000 babies in an African population are born with a severe form of sickle-cell anemia (ss), how many babies will be more resistant to malaria because they are heterozygous (Ss) for the sickle-cell gene?

Total babies are heterozygous (Ss) for the sickle-cell gene

Explanation:

It is given that babies with sickle cell anemia disease have genotype "ss"

The number of babies with sickle cell anemia disease

Out of , nearly species have ss genotype

Let us take "s" be recessive to "S"

Also let us assume that the given population is in Hardy Weinberg's equation-

Then frequency of recessive genotype would be

Frequency of recessive "s" allele will be

As per Hardy Weinberg's first equilibrium equation, we have -

Substituting the values of "q" in above equation, we get -

Frequency of dominant genotype would be

Hardy Weinberg's second equilibrium equation is

Substituting the available values in above equation we get -

Hence, % of babies are heterozygous (Ss) for the sickle-cell gene

Thus, total babies are heterozygous (Ss) for the sickle-cell gene

events in order:

1.       vishnu schist

2. zoroaster granite

3. bass limestone

4. hakatar   shale

5. igneous intrusion

6. shinumo quartzite

7. dox sandstone

8. tapeats limestone

9. bright angel shale

10. muav limestone

11. temple butte limestone

12. redwall limestone  

nonconformity

answer: the unkar group shows angular unconformity because the layers are turned at angle.

unconformity

answer: specifically the angular unconformity occurs between the cambrian and precambrian rocks. the dox sandstone, shinumo quartzite, hakatar shale, and bass limestone have been filled. an angular unconformity occurs between the cambrian and precambrian rocks. the dox sandstone, shinumo quartzite, hakatar shale, and bass limestone have been filled.

disconformity

answer: the disconformities aremarked irregular lines between the sedimentaryrocks layers.