An male animal has a genotype of AaBB. The number of different gene combinations that would be found in the sex cells/sperm of this animal would be:

a) 1
b) 2
c) 4
d) 6
e) 8

B

Explanation:

Using a Punnett Square, you find that the outcomes are AB, AB, aB, and aB. There are only two unique genotypes here, so the answer is 2.

the cladogram shown here shows similarities and differences among several classes of vertebrates. anatomically, the four have limb structure as their common ancestor. we might separate the mammals from the other three classes because they a) divergent; do not lay eggs b) identical; are warm-blooded c) varied; a four chambered heart d) homologous; have mammary glands