Suppose you have monohybrid pea plants in your garden and find that they produce round seed to wrinkled seeds in the ratio of 3:1. If the allele are designated (R & r) respectively, what is the probable Phenotype of the parents?

The parents are probably both phenotypically round-seeded with genotypes (Rr) each.

Explanation:

According to the question, a monohybrid cross involving a single gene coding for seed shape in pea plants is the case here. The allele for round seeds is R while allele for wrinkled seeds is r. The "R" allele is dominant over the "r" allele i.e. the phenotypic expression of r will be masked by R in a heterozygous state.

In order to get a ratio 3:1 of round seeds to wrinkled seeds offsprings, the parents will probably both have an Rr genotype, which is phenotypically round-seeded considering that round seeds (R) is dominant over wrinked seeds (r).

As seen in the punnet square attached as an image, four possible offsprings will be produced from a cross between parents Rr × Rr. The possible offsprings will have genotypes: RR, Rr, Rr, and rr.

RR, Rr, Rr are phenotypically round-seeded (3)

rr is phenotypically wrinkled-seeded (1).

Hence, the ratio 3 round seeds : 1 wrinkled seeds will be probably produced by parents with round seeds (Rr).

d. in sexual reproduction, offspring have more chromosomes than

either parent.

asexual reproduction results in offspring which are genetically the same as the parent organism (not counting a rare mutation). sexual reproduction produces a random mixture of the genetics derived from both parents

explanation:

check for the pregnancy rating of drug. if its class c or d see if other alternatives