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Biology, 04.07.2020 18:01 photagraphykid

1. You isolate some E. coli mutants which differ in their ability to break down maltose (a complex sugar) due to their differential synthesis of the enzyme maltase. You discover that the synthesis of the enzyme maltase is dependent on the presence or absence of maltose and glucose in the medium as follows: Maltase Activity - maltose maltose maltose - maltose Genotype glucose glucose glucose glucose Wild type - + - +Mutant -1 + + - - + = maltase activityMutant 2 - + + - - = no maltase activityMutant 3 - - - -Mutant 4 - - - -Genetic mapping data show that mutations 3 and 4 are tightly linked. Mutations 1 and 2 are both widely separated from 3 and 4 and from each other. A) Explain the behavior of wild type. B) Explain the behavior of mutants 1 and 2.C) What are two possible explanations for the behavior of mutants 3 and 4.2. Suppose E. coli is growing in a growth medium containing lactose as the sole source of carbon. The genotype is i z y". Glucose is thern added. Which one of the following will happen? A) The repressor will bind to the operator. B) Lactose will no longer be utilized by the cell. C) Lac mRNA will no longer be made. D) Nothing.

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