Calculate the rate of photosynthesis (mm/hr) for Elodea if when measuring net photosynthesis, the water level moved up 7mm from the initial level in 10 min, and when measuring cellular respiration it took 15 minutes for the water level to move down 1 mm.

The process of photosynthesis is commonly written as 6CO2 + 6H2O → C6H12O6 + 6O2.

With 6 we should always multiply gross photosynthesis (as we were measuring gross photosynthesis for 10 min).

This means that the reactants, six CO2 molecules, and 6 water molecules, are converted by light energy captured by chlorophyll (implied by the arrow) into a sugar molecule and 6 oxygen molecules, the products.

Gross photosynthesis = Net photosynthesis + respiration = 1.5+0.66 = 2.16 (mm/10min)

Rate of photosynthesis = (gross photosynthesis)6 = 2.16 *6 = 12.96 mm/hr

As we gauge the photosynthesis rate in hr.

Therefore, the correct calculation of photosynthesis is 6=2.16=12.96mm/hr.

Learn more about the photosynthesis calculation:

link

With 6 we should multiply gross photosynthesis (as we were measuring gross photosynthesis for 10 min).

Explanation:

According to this question:-

Net photosynthesis- 3mm/20min- 1.5mm/10min

Cellular respiration- 1mm/15min- 0.66mm/10min

Gross photosynthesis = Net photosynthesis + Cellular respiration = 1.5+0.66 = 2.16 (mm/10min)

Rate of photosynthesis = (gross photosynthesis)6 = 2.16 *6 = 12.96 mm/hr

As we gage the photosynthesis rate in hr.

is in the form atp or adenosine triphosphate

sheep is a herbivore animal whereas grasshopper belongs to the class chordates but both of them feed on greens.  

if grasshopper and sheep feeding on a pasture land, i do not think both of them will have any impact on each other. however, the number of the species can make difference. since sheep feed on greens, there is a possibility there left no pasture land for the grasshoppers or they may get extinct.