150 ml of 54% CaCI2 solution contains how many grams of CaCI2?

mass of CaCl₂ = 67.4 g of CaCl₂

Explanation:

A 45% CaCl₂ Solution contains 45 g of solute per 100 mL of solution.

mass concentration = mass of solute (g)/ volume of solution (L)

100 mL of solution = 100 * 1L /1000 = 0.1 L

Mass concentration of solution = 45 g/0.1 L = 450 g/L

Molar concentration of solution = mass concentration / molar mass

molar mass of CaCl₂  = 111 g/mol

molar concentration = 450 g/L / 111 g/mol = 4. 05 mol/L

Number of moles of CaCl₂ present in 150 ml of 4.05 mol/L  solution = molar concentration *  volume (L)

number of moles of CaCl₂  = 4.05 * 150 * 1 L/1000 = 0.6075 moles

mass of CaCl₂  present in 0.6075 moles  = number of moles * molar mass

mass of CaCl₂ = 0.6075 * 111 = 67.4 g of CaCl₂

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