To study the fate of carbon during glycolysis under aerobic conditions, cultured cells are fed with 14C-glucose labeled in various positions. You use a radiolabeled form of glucose where the radioactive 14C occupies position 1. Which of the following is correct?a. The carboxyl group of acetyl-CoA and CO2 become radiolabeledb. The methyl group of acetyl CoA and CO2 become radiolabeledc. The carbonyl group of acetyl-CoA becomes radiolabeledd. The methyl group of acetyl CoA becomes radiolabelede. CO2 becomes radiolabeledf. I don’t have enough information to conclude

D. The methyl group of acetyl CoA becomes radio-labeled

Explanation:

During the steps in glycolysis, the carbon at position 1, becomes C-1 in dihydroxyacetone phosphate during the cleavage of fructose-1,6-bisphosphate to dihydroxyacetone phosphate and glyceraldehyde-3-phosphate. Subsequently on isomerization of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate, C-1 of dihydroxyacetone phosphate becomes C-3 of glyceraldehyde-3-phosphate.

Furthermore, in pyruvate, the end product of glycolysis, C-3 is converted to a methyl group which then becomes the methyl group in the acetyl-CoA molecule produced from the oxidative decarboxylation of pyruvate.

Since the radioactive 14-C of radio-labeled glucose occupies position 1, it will become the methyl group of acetyl-CoA.

the element that provides strength to the exoskeletons of clams and oysters is phosphorus.

this is so because calcium carbonate is the main component in the shells. calcium carbonate is strengthened by phosphorus.

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