a man went from his home to market 3 kilometre away with a uniform speed of 4 kilometre per hour and finding the market closed Thi intense turns back with a velocity of 6 km per hour or find average speed of his journey

The average speed of his journey is 4.8 kilometre per hour

Explanation:

The given parameters are;

The distance from the man's home to the market  = 3 km

The man's speed on his way to the market = 4 km/h

The man's speed on his way back to his home  = 6 km/h

The average speed, s = The total distance, d divided by the time, t that elapsed during the journey

s = d/t

We note that time = Distance/Speed

The time it took the man to get to the market = Distance/Speed

The time it took the man to get to the market = 3 km/(4 km/hr) = 3/4 hours

The time it took the man to get to get back to his home = 3 km/(6 km/hr)  = 1/2 hours

The total time to and from the market = 3/4 + 1/2 = 5/4 hours = 1.25 hours

The total distance covered by the man = 3 + 3 = 6 km

The average speed, s = 6 km/(1.25 hours) = 4.8 km/hr

The average speed of his journey = 4.8 km/hr.

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